10 Width

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How would the strength of a beam change if the width and length are doubled?

Math question its a Strength of a beam problem. The problem begins like this " Using the the Strength of a Beam Model, the strength (s) of a beam is directly proportional to its width(w) and the square of its depth (d), and inversely proportional to its length(I).

s= w*d^0.5*1/L

Say length was 10, width is 2 height is 2

s=0.2828

Say the length was 20 width was 4 and height says at 2

s= 0.2828

Strength of the beam stays the same

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